25x^2-20x-2=6

Solution for 25x^2-20x-2=6 equation:

25x^2-20x-2=6

We move all terms to the left:

25x^2-20x-2-(6)=0

We add all the numbers together, and all the variables

25x^2-20x-8=0

a = 25; b = -20; c = -8;
Δ = b2-4ac
Δ = -202-4·25·(-8)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{3}}{2*25}=\frac{20-20\sqrt{3}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{3}}{2*25}=\frac{20+20\sqrt{3}}{50}
$